What You'll Need
To complete the square by hand, gather these supplies and tools:
- Paper – for writing out the steps.
- Pencil – easy to erase mistakes.
- Eraser – you'll likely need it.
- Scientific calculator – optional, for checking arithmetic or square roots.
If you need a refresher on the definition and purpose, read our What Is Completing the Square? Guide.
Step-by-Step Method
Follow these steps to rewrite any quadratic equation from standard form ax² + bx + c = 0 into vertex form a(x - h)² + k.
- Write the equation in standard form. Make sure it's
ax² + bx + c = 0. If it's not, rearrange terms. - If a ≠ 1, factor a out of the x² and x terms. Rewrite as
a(x² + (b/a)x) + c = 0. (Leave the constant c outside.) - Take half of the coefficient of x (inside the parentheses), square it, and add and subtract that value inside. For
x² + (b/a)x, half is(b/(2a)), square is(b/(2a))². So you geta[x² + (b/a)x + (b/(2a))² - (b/(2a))²] + c. - Group the perfect square trinomial. The first three terms inside form
(x + b/(2a))². Writea[(x + b/(2a))² - (b/(2a))²] + c. - Distribute a and combine constants. Multiply
athrough:a(x + b/(2a))² - a*(b/(2a))² + c. Simplify the constant:k = c - (b²)/(4a). The vertex form isa(x - h)² + kwhereh = -b/(2a). (Note: the sign inside the parentheses flips:(x + b/(2a))becomes(x - h)becauseh = -b/(2a).)
For a deeper look at the formula behind these steps, check out our Completing the Square Formula Derivation.
Worked Example 1: a = 1
Consider x² + 6x + 5 = 0.
- Standard form: already set.
- a = 1, so no factoring needed.
- Coefficient of x is 6. Half is 3, square is 9. Add and subtract inside:
x² + 6x + 9 - 9 + 5 = 0. - Perfect square:
(x + 3)² - 9 + 5 = 0→(x + 3)² - 4 = 0. - Vertex form:
(x + 3)² - 4 = 0, soa = 1,h = -3,k = -4. The vertex is (-3, -4).
Worked Example 2: a ≠ 1
Solve 2x² + 8x - 10 = 0.
- Standard form: fine.
- a = 2, so factor:
2(x² + 4x) - 10 = 0. - Inside x²+4x: half of 4 is 2, square is 4. Add and subtract:
2(x² + 4x + 4 - 4) - 10 = 0. - Group:
2[(x + 2)² - 4] - 10 = 0. - Distribute:
2(x + 2)² - 8 - 10 = 0→2(x + 2)² - 18 = 0. Vertex form:2(x + 2)² - 18 = 0, soh = -2,k = -18. Vertex = (-2, -18).
After rewriting in vertex form, you can analyze the parabola's properties. Learn how in our Results Interpretation Guide.
Common Pitfalls
- Forgetting to factor out a when a ≠ 1. Many students skip step 2, leading to wrong constants.
- Sign errors when taking half and squaring. Always square after halving, and watch the sign of b.
- Neglecting to multiply the added-and-subtracted square by a. When you distribute a later, the subtracted term is multiplied by a (as we did in example 2).
- Mishandling the constant sign. When moving the constant to the other side, keep it equal. Possibly double-check your arithmetic.
- Confusing vertex form. Remember
a(x - h)² + k; the sign inside is opposite of h.
Practice with different coefficients. Use our Completing The Square Calculator to verify your steps.
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